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Eol Resistor


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Im fitting my Pyronix DT PIR's which (in my old house, not installed by me) didnt use the built in EOL resistors but had them all in the panel.

 

I want to make this one a bit neater and somewhat more "proper job".

 

Im guessing the clue is in the title - END of Line - that the resistors need to be within the housing of the detector and not within the panel.

 

I need 1k closed and 2k open - i can get the first 1k from the built in resistors, but my issue now is physically, how would I fit the second 1k resistor into this space...

 

IMG_20150708_113853.jpg

 

and does the tamper work on the same 1k/2k principle ?

'till the next question ...

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manuals eh .... who'd of thought. 

 

they went with the old house .... 

 

I thought this sensor only gave me just one set of resistors to play with not both,

 

I'll go google

'till the next question ...

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I have the instructions, but im just a little stuck with the setup here. I had it working fine with a 1k resistor in the panel and the zone wired into the ALM terminals and the ALM jumper set to 1k.

 

If i move one of the ALM wires over to the TAM terminal as suggested in the diagram the panel reports Open Circuit Tamper (infinite resistance).

 

wireup.jpg

'till the next question ...

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I was just being a daffy diyer

 

With the cover open the tamper caused the open circuit.

 

closed up the cover and the values kicked in. although i had set 1k and 2k which gave me 3k I quickly fixed it.

 

Pro in the making here! 

 

cheers all.

'till the next question ...

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