hi, i am a newbie in the cctv systems.

i have some problems in calculating the storage needs in a cctv system.

i know that the factors that i have to considered when calculating storage needs are:

-number of cameras

-number of hours per day, that the camera will be recording

-how long the data must be stored

- frame rate , compression, image quality and complexity

for the bellow exemple (per example) :

if i have 1 camera whit:

resolution= 640 * 480

frames per second=25

period of storage= 8 hours

compression = MJPEG (50)

i know that i have to use this formula (FOR 1 CAMERA):

required storage space=image size* frames per second * period of request

my principal question is how i can calculating the image size?

and how resolution and compression influences the image size?

and for the case that i use the m4peg?

how can i know the storage requeried ?

how can i know the bandwidth requeried ?

can anybody help me?

best regards

I would allow 15-20gb per camera for 8 hours@25fps although I estimate about 19gb.

attached is a storage chart from dedicated micros, they say 25k equates to better than 400 tv lines.

storagechart.pdf

thanks for your help...

i have seen your attached, but i don